Различия
Показаны различия между двумя версиями страницы.
| Предыдущая версия справа и слева Предыдущая версия Следующая версия | Предыдущая версия | ||
| math:2-14 [2023/06/07 12:38] – root | math:2-14 [2023/06/07 12:56] (текущий) – [47.7.] root | ||
|---|---|---|---|
| Строка 5: | Строка 5: | ||
| $F=e^{1}\otimes e_{2}+e^{2}\otimes (e_{1}+3e_3)\in\mathbb{T}_{1}^{1}\left(V\right), | $F=e^{1}\otimes e_{2}+e^{2}\otimes (e_{1}+3e_3)\in\mathbb{T}_{1}^{1}\left(V\right), | ||
| где $v=e_{1}+5e_{2}+4e_{3}$, | где $v=e_{1}+5e_{2}+4e_{3}$, | ||
| + | |||
| + | ----- | ||
| Для того чтобы вычислить $F(v,f)$, нужно подставить значения $v$ | Для того чтобы вычислить $F(v,f)$, нужно подставить значения $v$ | ||
| и $f$ в $F$: | и $f$ в $F$: | ||
| - | $F(v, | + | $$F(v, |
| - | $e^{1}\left(e_{1}\right)\otimes e_{2}\left(e^{2}\right)+e^{2}\left(5e_{2}\right)\otimes (e_{1}\left(e^{1}\right)+3e_{3}\left(e^{3}\right))=1\otimes 1+5\otimes 4=21$ | + | $$e^{1}\left(e_{1}\right)\otimes e_{2}\left(e^{2}\right)+e^{2}\left(5e_{2}\right)\otimes (e_{1}\left(e^{1}\right)+3e_{3}\left(e^{3}\right))=1\otimes 1+5\otimes 4=21.$$ |
| ==== 47.3. ==== | ==== 47.3. ==== | ||
| Строка 19: | Строка 21: | ||
| === a) === | === a) === | ||
| - | $A=e_{1}\otimes | + | $A=e_{1}\otimes |
| - | $B=e1\otimes | + | $B=e_1\otimes |
| - | $v_{1}=e1,v2=e1+e2,v3=e2+e3,v4=v5=e2$ | + | $v_{1}=e_1,v_2=e_1+e_2,v_3=e_2+e_3,v_4=v_5=e_2$ |
| - | $B=e1\otimes e2\otimes \left(e1-e3\right)$ | + | ----- |
| - | $A=e1\left(e1\right)\otimes | + | $B=e_1\otimes e_2\otimes \left(e_1-e_3\right)$ |
| + | |||
| + | $A=e_1\left(e_1\right)\otimes | ||
| $1\otimes 1+0\otimes 0+0\otimes 1=1$ | $1\otimes 1+0\otimes 0+0\otimes 1=1$ | ||
| - | $B=e1\left(e2+e3\right)\otimes | + | $B=e_1\left(e_2+e_3\right)\otimes |
| тогда $A\otimes B(v)=0$ | тогда $A\otimes B(v)=0$ | ||
| - | $B=e1\left(e1\right)\otimes | + | $B=e_1\left(e_1\right)\otimes |
| - | $A=e1\left(e2\right)\otimes | + | $A=e_1\left(e_2\right)\otimes |
| тогда $B\otimes A(v)=-1$ | тогда $B\otimes A(v)=-1$ | ||
| Строка 45: | Строка 49: | ||
| === б) === | === б) === | ||
| - | $A=e1\otimes | + | $A=e_1\otimes |
| + | |||
| + | $B=\sum e_i\otimes e_j\otimes e_k$ | ||
| - | $B=\sum ei\otimes ej\otimes ek$ | + | $v_1=e_1+e_2, |
| - | $v1=e1+e2, | + | ----- |
| - | $A=e1\left(e1+e2\right)\otimes | + | $A=e_1\left(e_1+e_2\right)\otimes |
| $1\otimes 1+1\otimes 1+0\otimes 0=2$ | $1\otimes 1+1\otimes 1+0\otimes 0=2$ | ||
| - | $B=\sum | + | $B=\sum |
| - | $A=e1\left(e2\right)\otimes | + | $A=e_1\left(e_2\right)\otimes |
| - | $B=\sum | + | $B=\sum |
| Тогда | Тогда | ||
| Строка 80: | Строка 86: | ||
| и $B\otimes A$ тензоров | и $B\otimes A$ тензоров | ||
| - | $A=e1\otimes | + | $A=e_1\otimes |
| - | $B=\det\left(v1,v2,v3\right)$ | + | $B=\det\left(v_1,v_2,v_3\right)$ |
| - | $A\otimes B\left(e1,e2,e3,e3,e3\right)=A\left(e1,e2\right)\otimes B\left(e3,e3,e3\right)=A\left(e1,e2\right)\otimes 0=0$ | + | $A\otimes B\left(e_1,e_2,e_3,e_3,e_3\right)=A\left(e_1,e_2\right)\otimes B\left(e_3,e_3,e_3\right)=A\left(e_1,e_2\right)\otimes 0=0$ |
| - | $B\otimes A\left(e1,e2,e3,e3,e3\right)=B\left(e1,e2,e3\right)\otimes A\left(e3,e3\right)=B\left(e1,e2,e3\right)\otimes \left(e1\left(e3\right)\otimes | + | $B\otimes A\left(e_1,e_2,e_3,e_3,e_3\right)=B\left(e_1,e_2,e_3\right)\otimes A\left(e_3,e_3\right)=B\left(e_1,e_2,e_3\right)\otimes \left(e_1\left(e_3\right)\otimes |
| ==== 47.7. ==== | ==== 47.7. ==== | ||
| Строка 96: | Строка 102: | ||
| в базисе | в базисе | ||
| - | $(\widetilde{e_{1}}, | + | $$(\widetilde{e_{1}}, |
| 1 & 1\\ | 1 & 1\\ | ||
| 2 & 3 | 2 & 3 | ||
| - | \end{array}\right)$ | + | \end{array}\right)$$ |
| - | $(e_{1}, | + | $$(e_{1}, |
| 1 & 1\\ | 1 & 1\\ | ||
| 2 & 3 | 2 & 3 | ||
| Строка 107: | Строка 113: | ||
| 3 & -1\\ | 3 & -1\\ | ||
| -2 & 1 | -2 & 1 | ||
| - | \end{array}\right)$ | + | \end{array}\right)$$ |
| - | $(e^{1}, | + | $$(e^{1}, |
| 1 & 1\\ | 1 & 1\\ | ||
| 2 & 3 | 2 & 3 | ||
| - | \end{array}\right)$ | + | \end{array}\right)$$ |
| - | $\widetilde{t_{jk}^{i}}=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (3\widetilde{e_{1}}-2\widetilde{e_{2}}-\widetilde{e_{1}}+\widetilde{e_{2}})=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (2\widetilde{e_{1}}-\widetilde{e_{2}})$ | + | $$\widetilde{t_{jk}^{i}}=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (3\widetilde{e_{1}}-2\widetilde{e_{2}}-\widetilde{e_{1}}+\widetilde{e_{2}})=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (2\widetilde{e_{1}}-\widetilde{e_{2}})$$ |
| - | $\widetilde{t_{21}^{1}}=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (2\widetilde{e_{1}}-\widetilde{e_{2}})\left(\widetilde{e_{2}}, | + | $$\widetilde{t_{21}^{1}}=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (2\widetilde{e_{1}}-\widetilde{e_{2}})\left(\widetilde{e_{2}}, |
| - | $\left(\widetilde{e^{1}}\left(\widetilde{e_{2}}\right)+2\widetilde{e^{2}}\left(\widetilde{e_{2}}\right)\right)\otimes \left(\widetilde{e^{1}}\left(\widetilde{e_{1}}\right)+3\widetilde{e^{2}}\left(\widetilde{e_{1}}\right)\right)\otimes (2\widetilde{e_{1}}\left(\widetilde{e^{1}}\right)-\widetilde{e_{2}}\left(\widetilde{e^{1}}\right))=$ | + | $$\left(\widetilde{e^{1}}\left(\widetilde{e_{2}}\right)+2\widetilde{e^{2}}\left(\widetilde{e_{2}}\right)\right)\otimes \left(\widetilde{e^{1}}\left(\widetilde{e_{1}}\right)+3\widetilde{e^{2}}\left(\widetilde{e_{1}}\right)\right)\otimes (2\widetilde{e_{1}}\left(\widetilde{e^{1}}\right)-\widetilde{e_{2}}\left(\widetilde{e^{1}}\right))=$$ |
| - | $\left(0+2\right)\otimes \left(1+3\cdot0\right)\otimes (2-0)=2\otimes 1\otimes 2=4$ | + | $$\left(0+2\right)\otimes \left(1+3\cdot0\right)\otimes (2-0)=2\otimes 1\otimes 2=4$$ |
| - | ==== 47.13. ==== Найти полную свертку тензоров: | + | ==== 47.13. ==== |
| + | Найти полную свертку тензоров: | ||
| === a) === | === a) === | ||