Различия
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| Следующая версия | Предыдущая версия | ||
| math:2-14 [2023/06/07 12:36] – создано root | math:2-14 [2023/06/07 12:56] (текущий) – [47.7.] root | ||
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| Строка 1: | Строка 1: | ||
| - | 47.2. Найти значение $F(v,f)$ тензора | + | ==== 47.2. ==== |
| - | $F=e^{1}\otimes e_{2}+e^{2}\otimes (e_{1}+\lyxmathsym{З}\lyxmathsym{е}_{3})\in\mathbb{T}_{1}^{1}\left(V\right), | + | Найти значение $F(v,f)$ тензора |
| + | |||
| + | $F=e^{1}\otimes e_{2}+e^{2}\otimes (e_{1}+3e_3)\in\mathbb{T}_{1}^{1}\left(V\right), | ||
| где $v=e_{1}+5e_{2}+4e_{3}$, | где $v=e_{1}+5e_{2}+4e_{3}$, | ||
| + | |||
| + | ----- | ||
| Для того чтобы вычислить $F(v,f)$, нужно подставить значения $v$ | Для того чтобы вычислить $F(v,f)$, нужно подставить значения $v$ | ||
| и $f$ в $F$: | и $f$ в $F$: | ||
| - | $F(v, | + | $$F(v, |
| - | $e^{1}\left(e_{1}\right)\otimes e_{2}\left(e^{2}\right)+e^{2}\left(5e_{2}\right)\otimes (e_{1}\left(e^{1}\right)+3e_{3}\left(e^{3}\right))=1\otimes 1+5\otimes 4=21$ | + | $$e^{1}\left(e_{1}\right)\otimes e_{2}\left(e^{2}\right)+e^{2}\left(5e_{2}\right)\otimes (e_{1}\left(e^{1}\right)+3e_{3}\left(e^{3}\right))=1\otimes 1+5\otimes 4=21.$$ |
| - | 47.3. Найти значение тензора $A\otimes B-B\otimes A\in\mathbb{T}_{5}^{0}\left(V\right)$ | + | ==== 47.3. ==== |
| + | Найти значение тензора $A\otimes B-B\otimes A\in\mathbb{T}_{5}^{0}\left(V\right)$ | ||
| от набора | от набора | ||
| - | a) $A=e_{1}\otimes e2+e2\otimes e3+e2\otimes e2$ | + | === a) === |
| - | $B=e1\otimes | + | $A=e_{1}\otimes |
| - | $v_{1}=e1, | + | $B=e_1\otimes e_2\otimes \left(e_1-e_3\right)$ |
| - | $B=e1\otimes e2\otimes \left(e1-e3\right)$ | + | $v_{1}=e_1, |
| - | $A=e1\left(e1\right)\otimes | + | ----- |
| + | |||
| + | $B=e_1\otimes e_2\otimes \left(e_1-e_3\right)$ | ||
| + | |||
| + | $A=e_1\left(e_1\right)\otimes | ||
| $1\otimes 1+0\otimes 0+0\otimes 1=1$ | $1\otimes 1+0\otimes 0+0\otimes 1=1$ | ||
| - | $B=e1\left(e2+e3\right)\otimes | + | $B=e_1\left(e_2+e_3\right)\otimes |
| тогда $A\otimes B(v)=0$ | тогда $A\otimes B(v)=0$ | ||
| - | $B=e1\left(e1\right)\otimes | + | $B=e_1\left(e_1\right)\otimes |
| - | $A=e1\left(e2\right)\otimes | + | $A=e_1\left(e_2\right)\otimes |
| тогда $B\otimes A(v)=-1$ | тогда $B\otimes A(v)=-1$ | ||
| Строка 38: | Строка 47: | ||
| следовательно $\left(A\otimes B-B\otimes A\right)\left(v\right)=0-(-1)=1$ | следовательно $\left(A\otimes B-B\otimes A\right)\left(v\right)=0-(-1)=1$ | ||
| - | б) $A=e1\otimes e2+e2\otimes e3+e3\otimes e1$ | + | === б) === |
| - | $B=\sum ei\otimes | + | $A=e_1\otimes e_2+e_2\otimes |
| - | $v1=e1+e2, | + | $B=\sum e_i\otimes e_j\otimes e_k$ |
| - | $A=e1\left(e1+e2\right)\otimes | + | $v_1=e_1+e_2, |
| + | |||
| + | ----- | ||
| + | |||
| + | $A=e_1\left(e_1+e_2\right)\otimes | ||
| $1\otimes 1+1\otimes 1+0\otimes 0=2$ | $1\otimes 1+1\otimes 1+0\otimes 0=2$ | ||
| - | $B=\sum | + | $B=\sum |
| - | $A=e1\left(e2\right)\otimes | + | $A=e_1\left(e_2\right)\otimes |
| - | $B=\sum | + | $B=\sum |
| Тогда | Тогда | ||
| Строка 58: | Строка 71: | ||
| $A\otimes B-B\otimes A=2\otimes 2-8\otimes 0=4$ | $A\otimes B-B\otimes A=2\otimes 2-8\otimes 0=4$ | ||
| - | 47.4. Найти значение $F\left(v, | + | ==== 47.4. ==== |
| + | |||
| + | Найти значение $F\left(v, | ||
| если все координаты тензора $F$ равны 3, и | если все координаты тензора $F$ равны 3, и | ||
| Строка 67: | Строка 82: | ||
| $F=3\sum e^{i}\left(e_{1}+2e_{2}+3e_{3}+4e_{4}\right)\otimes e^{j}\left(e_{1}+2e_{2}+3e_{3}+4e_{4}\right)\otimes e^{k}\left(e_{1}+2e_{2}+3e_{3}+4e_{4}\right)\otimes e_{l}\left(e^{1}-e^{4}\right)\otimes e_{m}\left(e^{1}-e^{4}\right)=0$ | $F=3\sum e^{i}\left(e_{1}+2e_{2}+3e_{3}+4e_{4}\right)\otimes e^{j}\left(e_{1}+2e_{2}+3e_{3}+4e_{4}\right)\otimes e^{k}\left(e_{1}+2e_{2}+3e_{3}+4e_{4}\right)\otimes e_{l}\left(e^{1}-e^{4}\right)\otimes e_{m}\left(e^{1}-e^{4}\right)=0$ | ||
| - | 47.6. Найти координаты с индексами 1, 2, 3, 3, 3 произведений $A\otimes B$ | + | ==== 47.6. ==== |
| + | Найти координаты с индексами 1, 2, 3, 3, 3 произведений $A\otimes B$ | ||
| и $B\otimes A$ тензоров | и $B\otimes A$ тензоров | ||
| - | $A=e1\otimes | + | $A=e_1\otimes |
| - | $B=\det\left(v1,v2,v3\right)$ | + | $B=\det\left(v_1,v_2,v_3\right)$ |
| - | $A\otimes B\left(e1,e2,e3,e3,e3\right)=A\left(e1,e2\right)\otimes B\left(e3,e3,e3\right)=A\left(e1,e2\right)\otimes 0=0$ | + | $A\otimes B\left(e_1,e_2,e_3,e_3,e_3\right)=A\left(e_1,e_2\right)\otimes B\left(e_3,e_3,e_3\right)=A\left(e_1,e_2\right)\otimes 0=0$ |
| - | $B\otimes A\left(e1,e2,e3,e3,e3\right)=B\left(e1,e2,e3\right)\otimes A\left(e3,e3\right)=B\left(e1,e2,e3\right)\otimes \left(e1\left(e3\right)\otimes | + | $B\otimes A\left(e_1,e_2,e_3,e_3,e_3\right)=B\left(e_1,e_2,e_3\right)\otimes A\left(e_3,e_3\right)=B\left(e_1,e_2,e_3\right)\otimes \left(e_1\left(e_3\right)\otimes |
| - | 47.7. Найти координаты: | + | ==== 47.7. ==== |
| + | Найти координаты: | ||
| - | a) $\widetilde{t_{21}^{1}}$ тензора $e^{1}\otimes e^{2}\otimes (e_{1}+e_{2})\in T_{2}^{1}(V)$ | + | === a) === |
| + | |||
| + | $\widetilde{t_{21}^{1}}$ тензора $e^{1}\otimes e^{2}\otimes (e_{1}+e_{2})\in T_{2}^{1}(V)$ | ||
| в базисе | в базисе | ||
| - | $(\widetilde{e_{1}}, | + | $$(\widetilde{e_{1}}, |
| 1 & 1\\ | 1 & 1\\ | ||
| 2 & 3 | 2 & 3 | ||
| - | \end{array}\right)$ | + | \end{array}\right)$$ |
| - | $(e_{1}, | + | $$(e_{1}, |
| 1 & 1\\ | 1 & 1\\ | ||
| 2 & 3 | 2 & 3 | ||
| Строка 94: | Строка 113: | ||
| 3 & -1\\ | 3 & -1\\ | ||
| -2 & 1 | -2 & 1 | ||
| - | \end{array}\right)$ | + | \end{array}\right)$$ |
| - | $(e^{1}, | + | $$(e^{1}, |
| 1 & 1\\ | 1 & 1\\ | ||
| 2 & 3 | 2 & 3 | ||
| - | \end{array}\right)$ | + | \end{array}\right)$$ |
| + | |||
| + | $$\widetilde{t_{jk}^{i}}=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (3\widetilde{e_{1}}-2\widetilde{e_{2}}-\widetilde{e_{1}}+\widetilde{e_{2}})=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (2\widetilde{e_{1}}-\widetilde{e_{2}})$$ | ||
| - | $\widetilde{t_{jk}^{i}}=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (3\widetilde{e_{1}}-2\widetilde{e_{2}}-\widetilde{e_{1}}+\widetilde{e_{2}})=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (2\widetilde{e_{1}}-\widetilde{e_{2}})$ | + | $$\widetilde{t_{21}^{1}}=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes (2\widetilde{e_{1}}-\widetilde{e_{2}})\left(\widetilde{e_{2}},\widetilde{e_{1}},\widetilde{e^{1}}\right)=$$ |
| - | $\widetilde{t_{21}^{1}}=\left(\widetilde{e^{1}}+2\widetilde{e^{2}}\right)\otimes \left(\widetilde{e^{1}}+3\widetilde{e^{2}}\right)\otimes | + | $$\left(\widetilde{e^{1}}\left(\widetilde{e_{2}}\right)+2\widetilde{e^{2}}\left(\widetilde{e_{2}}\right)\right)\otimes \left(\widetilde{e^{1}}\left(\widetilde{e_{1}}\right)+3\widetilde{e^{2}}\left(\widetilde{e_{1}}\right)\right)\otimes (2\widetilde{e_{1}}\left(\widetilde{e^{1}}\right)-\widetilde{e_{2}}\left(\widetilde{e^{1}}\right))=$$ |
| - | $\left(\widetilde{e^{1}}\left(\widetilde{e_{2}}\right)+2\widetilde{e^{2}}\left(\widetilde{e_{2}}\right)\right)\otimes \left(\widetilde{e^{1}}\left(\widetilde{e_{1}}\right)+3\widetilde{e^{2}}\left(\widetilde{e_{1}}\right)\right)\otimes (2\widetilde{e_{1}}\left(\widetilde{e^{1}}\right)-\widetilde{e_{2}}\left(\widetilde{e^{1}}\right))=$ | + | $$\left(0+2\right)\otimes \left(1+3\cdot0\right)\otimes (2-0)=2\otimes |
| - | $\left(0+2\right)\otimes \left(1+3\cdot0\right)\otimes (2-0)=2\otimes 1\otimes 2=4$ | + | ==== 47.13. ==== |
| + | Найти полную свертку тензоров: | ||
| - | 47.13. Найти полную свертку тензоров: | + | === a) === |
| - | a) $t_{i}^{j}=(e_{1}+3e_{2}-e_{3})\otimes (e^{1}-2e^{3}+3e^{4})-(e_{1}+e_{3})\otimes (e^{1}-3e^{3}+e^{4})$; | + | $t_{i}^{j}=(e_{1}+3e_{2}-e_{3})\otimes (e^{1}-2e^{3}+3e^{4})-(e_{1}+e_{3})\otimes (e^{1}-3e^{3}+e^{4})$; |
| $t_{i}^{i}=(e_{1})\otimes (e^{1})+(-e_{3})\otimes (-2e^{3})-(e_{1})\otimes (e^{1})-(e_{3})\otimes (-3e^{3})=1+2-1+3=5$ | $t_{i}^{i}=(e_{1})\otimes (e^{1})+(-e_{3})\otimes (-2e^{3})-(e_{1})\otimes (e^{1})-(e_{3})\otimes (-3e^{3})=1+2-1+3=5$ | ||